1Kg of real gas is heated from 18ºC to 93 ºC. Assuming Cv=1.466KJ/KgK. Then internal energy is ……
For real gas U=νCVT−aν2/VU=\nu C_VT-a\nu^2/VU=νCVT−aν2/V . So, if V=constV=constV=const then the change of
the internal energy of real gas is
ΔU=νCVΔT=mMcVMΔT=mcVΔT=\Delta U= \nu C_V\Delta T=\frac{m}{M} c_VM\Delta T=m c_V\Delta T=ΔU=νCVΔT=MmcVMΔT=mcVΔT=
=1⋅1466⋅(93°−18°)=109950 (J)=1\cdot 1466\cdot(93°-18°)=109950\ (J)=1⋅1466⋅(93°−18°)=109950 (J) . Answer
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