Question #264317

1Kg of real gas is heated from 18ºC to 93 ºC. Assuming Cv=1.466KJ/KgK. Then internal energy is ……

1
Expert's answer
2021-11-11T11:59:03-0500

For real gas U=νCVTaν2/VU=\nu C_VT-a\nu^2/V . So, if V=constV=const then the change of


the internal energy of real gas is


ΔU=νCVΔT=mMcVMΔT=mcVΔT=\Delta U= \nu C_V\Delta T=\frac{m}{M} c_VM\Delta T=m c_V\Delta T=


=11466(93°18°)=109950 (J)=1\cdot 1466\cdot(93°-18°)=109950\ (J) . Answer

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS