1Kg of real gas is heated from 18ºC to 93 ºC. Assuming Cv=1.466KJ/KgK. Then internal energy is ……
For real gas "U=\\nu C_VT-a\\nu^2\/V" . So, if "V=const" then the change of
the internal energy of real gas is
"\\Delta U= \\nu C_V\\Delta T=\\frac{m}{M} c_VM\\Delta T=m c_V\\Delta T="
"=1\\cdot 1466\\cdot(93\u00b0-18\u00b0)=109950\\ (J)" . Answer
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