Question #263775

A 10Ω resistor is connected in parallel to 32Ω resistor and a voltage source of 24V. Find the effective resistance and total current provided in the circuit. Determine the current in each of the resistors.

Expert's answer

Let's first find the effective resistance in case of the parallel connection of resistors:


Re=R1R2R1+R2=32 Ω×10 Ω32 Ω+10 Ω=7.62 Ω.R_e=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{32\ \Omega\times10\ \Omega}{32\ \Omega+10\ \Omega}=7.62\ \Omega.

Then, we can find the total current in the circuit as follows:


I=VRe=24 V7.62 Ω=3.15 A.I=\dfrac{V}{R_e}=\dfrac{24\ V}{7.62\ \Omega}=3.15\ A.


We can find the current in each of the resistors as follows:


I1=VR1=24 V32 Ω=0.75 A,I_1=\dfrac{V}{R_1}=\dfrac{24\ V}{32\ \Omega}=0.75\ A,I2=VR2=24 V10 Ω=2.4 A.I_2=\dfrac{V}{R_2}=\dfrac{24\ V}{10\ \Omega}=2.4\ A.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS