A sailboat tacking against the wind moves as follows: 4.2 km at 33° east of north, 3.6 km at 26° west of north, and 3.8 km at 41° east of north. The entire trip takes 1 h and 25 min. What is the displacement of the sailboat at the end of the trip?
x=4.2⋅sin33°−3.6⋅sin26°+3.8⋅sin41°=3.2 (km)x=4.2\cdot\sin33°-3.6\cdot\sin26°+3.8\cdot\sin41°=3.2\ (km)x=4.2⋅sin33°−3.6⋅sin26°+3.8⋅sin41°=3.2 (km)
y=4.2⋅cos33°+3.6⋅cos26°+3.8⋅cos41°=9.6 (km)y=4.2\cdot\cos33°+3.6\cdot\cos26°+3.8\cdot\cos41°=9.6\ (km)y=4.2⋅cos33°+3.6⋅cos26°+3.8⋅cos41°=9.6 (km)
r=3.22+9.62=10.1 (km)r=\sqrt{3.2^2+9.6^2}=10.1\ (km)r=3.22+9.62=10.1 (km) . Answer
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