Question

A 1500 g object is being pushed by an applied force and accelerates at 4.08 m/s2. what is the force applied if a frictional force is 62.5 n is acting on opposite direction?

Answer 1

By Newton's second law:

$$ma=F-f,\\ F=ma+f=1.5·4.08+62.5=68.62\text{ N}.$$