Question

A uniform solid cylinder of mass 2 kg and radius 10 cm so that it is free to rotate. A mass of 3 kg is suspended by string that wound around the cylinder. The system is released from the rest. If 5 revolutions by cylinder rotates, determine angular momentum of the cylinder. (Given I=1/2MR² for solid cylinder)

Answer 1

The angular momentum of the cylinder:

$$L=I\omega=\frac12 MR^2·2\pi n,\\\space\\ L=\frac12·2·0.1^2·2·3.14·5=3.14\text{ kg}·\text{m}.$$