Question #258448

12. An astronaut experiences a force of gravity on Earth of 800 N. Neptune has 17 times the mass and 3.9 times the radius of Earth. What would the astronaut weigh, in newtons, on Neptune?


1
Expert's answer
2021-10-31T18:13:28-0400

Given:

FE=800NF_E=800\:\rm N

MN=17MEM_N=17M_E

RN=3.9RER_N=3.9R_E


The force of gravity on an astronaut with mass mm at the surface of planet with mass MM and radius RR is given by

F=GMmR2F=G\frac{Mm}{R^2}

Hence

FNFE=MNMERE2RN2\frac{F_N}{F_E}=\frac{M_N}{M_E}*\frac{R_E^2}{R_N^2}

FNFE=171/3.92=1.1\frac{F_N}{F_E}=17*1/3.9^2=1.1

Finally

FN=FE1.1=8001.1=880NF_N=F_E*1.1=800*1.1=880\:\rm N


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