Question

Diane dives in a pool moving at 7.6m/s until reaching 8.42m from the diving board. Solve the following

A. The average acceleration of the diver as she travels through the water
B. Time the divers come to a stop
C. The speed of the diver after diving 5.87m

Answer 1

A The average acceleration is

$$a=\frac{v^ 2}{2d}=3.44\text{ m/s}^2.$$

B. The time is

$$T=\frac{v}{a}=2.21\text{ s}.$$

C. The speed after 5.87 m is

$$v=\sqrt{2ad}=6.35\text{ m/s}.$$