Question #247068

X,y,z are three points on a straight road. A car passes X with a speed of 5m/s and travels from X to y with a constant acceleration of 2m/s²


1
Expert's answer
2021-10-06T08:16:36-0400

I suppose the distance between XX and YY is given (say, dd ) and the question is to find the time in which the car travelled this distance. Let a=2m/s2a = 2m/s^2 be the acceleration of the car, and v0=5m/sv_0 = 5m/s its initial speed. Then the time can be found from the following kinematic equation:


d=v0t+at22d = v_0t + \dfrac{at^2}{2}

Substituting the exact value for dd and solving the resultant quadratic equation, one will find the time.


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