Question

find the components of momentum of a 0.25 kg ball thrown with an initial velocity of 15 m/s 30

Answer 1

By definition, the momentum is the velocity times mass. Thus, it is enough to find the components of velocity vector:

$$v_x = 15m/s\cdot \cos30\degree =15\cdot \dfrac{\sqrt3}{2}m/s = 7.5\sqrt3m/s\\ v_y = 15m/s\cdot \sin30\degree =15\cdot \dfrac{1}{2}m/s = 7.5m/s$$

The momentum is then:

$$p_x = mv_x = 0.25kg\cdot7.5\sqrt3m/s = 1.1875\sqrt3\dfrac{kg\cdot m}{s}\\ p_y = mv_y = 0.25kg\cdot7.5m/s = 1.1875\dfrac{kg\cdot m}{s}\\$$

Answer:

$$p_x =1.1875\sqrt3\dfrac{kg\cdot m}{s}\\ p_y = 1.1875\dfrac{kg\cdot m}{s}\\$$