Question #244560

The rectangle shown in a Figure has sides parallel to the x and y axes. The position vectors of two

corners are A = 10.0 m at 50.0° and B = 12.0 m at 30.0°. (a) Find the perimeter of the rectangle. (b) Find the magnitude

and direction of the vector from the origin to the upper right corner of the rectangle.


Expert's answer

Find the x- and y-projection of A and B:


Ax=10cos⁡50°,Ay=10sin⁡50°.Bx=12cos⁡30°,By=12sin⁡30°. a=Bx−Ax,b=Ay−By.p=2(a+b)=2(Bx−Ax+Ay−By)=11.2 m.A_x=10\cos50°,\\ A_y=10\sin50°.\\ B_x=12\cos30°,\\ B_y=12\sin30°.\\\space\\ a=B_x-A_x,\\ b=A_y-B_y.\\ p=2(a+b)=2(B_x-A_x+A_y-B_y)=11.2\text{ m}.


The y-coordinate of the top right corner is Ay so, having x-coordinate equal to Bx, the magnitude of R:


R=Bx2+Ay2=12.9 m,θ=arctan⁡AyBx=36°. R⃗=12.9∠36°.R=\sqrt{B_x^2+A_y^2}=12.9\text{ m},\\\theta=\arctan\frac{A_y}{B_x}=36°.\\\space\\ \vec R=12.9\angle36°.


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