Answer to Question #243903 in Physics for manaa

Question

A vector C has magnitude of 11 m/s and makes an angle 65° degree with the positive x-

axis, vector D has Cartesian co-ordinates Dx = 4m/s

2 and Dy = −3 m/s

2. Find the difference C⃗ -D�⃗ between

two vectors.

Answer 1

Given:

$C_x=11*\cos65^{\circ}=4.65\:\rm m/s$

$C_y=11*\sin65^{\circ}=9.97\:\rm m/s$

$D_x=4.00\:\rm m/s$

$D_y=-3.00\:\rm m/s$

The difference between two vectors:

$${\bf C}-{\bf D}=(C_x-D_x){\hat i}+(C_y-D_y){\hat j}$$ $$=(4.65-4.00){\hat i}+(9.97-(-3.00)){\hat j}\\ =0.65{\hat i}+13.0{\hat j}$$