Assume the coordinates of the Andromeda galaxy are
"\\vec r_A=r_A\\angle\\theta_A,"we were given the coordinates to where the observer moves the telescope:
"\\vec r_t=r_t\\angle\\theta_t." The resultant will be
"r=\\sqrt{(r_A\\cos\\theta_A+r_t\\cos\\theta_t)^2+(r_A\\sin\\theta_A+r_t\\sin\\theta_t)^2}=\\\\\n=\\sqrt{(r_A\\cos\\theta_A+55.2)^2+(r_A\\sin\\theta_A+28.1)^2},\\\\\\space\\\\\n\\theta_r=\\arctan\\frac{r_A\\sin\\theta_A+r_t\\sin\\theta_t}{r_A\\cos\\theta_A+r_t\\cos\\theta_t}=\\\\\\space\\\\\n=\\arctan\\frac{r_A\\sin\\theta_A+28.1}{r_A\\cos\\theta_A+55.2}."
Comments
Leave a comment