Question #243829

a) What is the Young’s modulus of a metal if the speed of the sound in a rod is 4550 m/s and it’s density is p=5230 kg/m3?

b) A sound wave propagates through a 10 cm closed tube. The air temperature is -8 Celsius degrees. Calculate the second and third harmonics.


1
Expert's answer
2021-09-28T16:55:10-0400

a) v=E/ρE=v2ρ=455025230=108.3 (GPa)v=\sqrt{E/\rho}\to E=v^2\rho=4550^2\cdot5230=108.3\ (GPa)


b) f=nv2Lf=\frac{nv}{2L} ; v=γRTM=1.48.312650.029=326 (m/s)v=\sqrt{\gamma\frac{RT}{M}}=\sqrt{1.4\cdot\frac{8.31\cdot265}{0.029}}=326\ (m/s)


f2=232620.1=3260 (Hz)f_2=\frac{2\cdot326}{2\cdot0.1}=3260\ (Hz)


f3=332620.1=4890 (Hz)f_3=\frac{3\cdot326}{2\cdot0.1}=4890\ (Hz)


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS