Question

An empty swimming pool with a square floor dimension has a volume of 3y2 m3. Given the weight of air in the swimming pool is about 500 N and the air density is 1.29 kg/m3.

Find the length of the swimming pool’s floor, y.

Answer 1

$P=mg=\rho Vg=\rho\cdot3y^2\cdot g \to y=\sqrt{P/(3\rho g)}=$

$=\sqrt{500/(3\cdot1.29\cdot9.81)}=3.63\ (m)$