Answer to Question #239738 in Physics for sam

Question

A military helicopter on a training mission is flying horizontally at a speed of 60.0 m/s and accidentally drops a bomb (fortunately not armed) at an elevation of 300 m. You can ignore air resistance.

(a) How much time is required for the bomb to reach the earth?

(b) How far does it travel horizontally while falling?

(c) Find the horizontal and vertical components of its velocity just before it strikes the earth.

(d) Draw x-t, y-t, vx-t, and vy-t graphs for the bomb's motion.

(e) If the velocity of the helicopter remains constant, where is the helicopter when the bomb hits 

Answer 1

(a) The time is

$$t=\sqrt{\frac{2h}{g}}=7.82\text{ s}.$$

(b) The horizontal distance is

$$R=v_xt=60·7.382=443\text{ m}.$$

(c) The components are

$$v_x=60\text{ m/s},\\ v_y=gt=76.6\text{ m/s}.$$

(d) The graphs are below:

(e) Right above the bomb