Question #239674

What must be the velocity magnitude of the automobile (from rest) after 4 seconds of travel if its acceleration is a = 2t m/s^2 along positive x-axis?



1
Expert's answer
2021-09-22T07:06:38-0400

The velocity will be


v=0tatdt=0t(2t)tdt=042t2dt=23t304= =23(4303)=42.67 m/s.v=\int^t_0at\text dt=\int^t_0(2t)t\text dt=\int_0^42t^2\text dt=\frac23t^3\bigg|^4_0=\\\space\\ =\frac23(4^3-0^3)=42.67\text{ m/s}.


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