Question

A diving bell is to be designed to withstand the pressure of seawater at a depth of

900 m.

Answer 1

The pressure under water is given as follows:

$$p = \rho g h$$

where $h = 900m$ is the depth, $g\approx 9.81m/s^2$ is the gravitational acceleration, $\rho = 1025kg/m^3$ is the density of seawater. Thus, obtain:

$$p = 1025kg/m^3\cdot 9.81m/s^2\cdot 900m \approx 9.05\times 10^6Pa$$

Answer. $9.05\times 10^6Pa$.