Given:
∣q1∣=∣q2∣=e=1.6∗10−19C
d=d1+d2=0.30nm+0.10nm=0.40nm
E=120N/C
The electric dipole moment is given by
p=qd=1.6∗10−19∗0.40∗10−9=6.4−29C⋅mThe torque experienced by the molecule
τ=p×EThe maximum torque
τ=pE=6.4−29∗120=7.7∗10−27N⋅mThe minimum torque
τ=0
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