a uniform disc of radius R metre and mass M kg can rotate without friction on an axle passing through it's centre and perpendicular to it's plane. a cord is round at the rim of the disc and a homogenous force of F n is applied on the cord. evaluate the tangental acceleration of a point on the rim of the disc
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Expert's answer
2021-08-27T08:28:53-0400
The Newton's second law for rotational motion says
"I\\beta=\\tau"
or
"\\frac{MR^2}{2}*\\frac{a_{\\tau}}{R}=F*R"
Hence, the tangental acceleration of a point on the rim of the disc
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