Answer to Question #215298 in Physics for Sera

Question

The bottom of the bar is hinged to the wall, and the upper end of the bar is attached to the wall by means of a rope which makes 45 degrees with the wall. If the uniform bar weighs 400 N and makes 60o with the wall, find (a) the tension in the rope and (b) the horizontal and vertical forces exerted by the wall at the pivot.

Answer 1

a)

$$\frac{T}{\sin{60}}=\frac{400}{\sin{180-45-60}}\\T=357\ N$$

b)

$$R_x=357\sin{60}=309\ N\\R_y=400-357\cos{60}=222\ N$$