Question #215298

The bottom of the bar is hinged to the wall, and the upper end of the bar is attached to the wall by means of a rope which makes 45 degrees with the wall. If the uniform bar weighs 400 N and makes 60o with the wall, find (a) the tension in the rope and (b) the horizontal and vertical forces exerted by the wall at the pivot.


1
Expert's answer
2021-07-15T13:52:13-0400

a)


Tsin60=400sin1804560T=357 N\frac{T}{\sin{60}}=\frac{400}{\sin{180-45-60}}\\T=357\ N

b)


Rx=357sin60=309 NRy=400357cos60=222 NR_x=357\sin{60}=309\ N\\R_y=400-357\cos{60}=222\ N


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