Answer to Question #210455 in Physics for Day

Question

An asteroid with a diameter of 11km and a mass of 4.3 x 1015 kg impacts the earth at a speed of 31414m/s, landing in the Pacific Ocean. If 1.23% of the asteroid's kinetic energy goes to boiling the ocean water (assume an initial water temperature of 12°C), what volume of ocean water in L) will be boiled away by the collision? Assume ocean water is just plain water.

Answer 1

$$0.5kmv^2=\rho RV\\ 0.5(0.0123)(4.3\cdot10^{15})(31414)^2\\=(10^3)(2.26\cdot10^{6})V\\V=1.15\cdot10^{10}\ L$$