Answer to Question #210431 in Physics for enyewowwow

Question #210431

A charge of 3µC is used to test the electric field of a central charge of 6C that causes a force of 800N. What is the magnitude of the electric field?

Expert's answer

"F=qE\\to E=F\/q=800\/(3\\cdot10^{-6})=267\\cdot10^6\\ (V\/m)" . Answer

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