Consider a triangle ACD. GH is the midline because G and H are midpoints of AD and CD. Thus, AC=2GH.
According to the famous theorem, the sum of two sides of triangle are always greater than the third side. Consider triangle ABC. As we see, AC, being the common base for triangles ABC and ACD, is equal to 2GH. And since in triangle ABC AB+BC>AC by the mentioned theorem, and in triangle ACD AD+CD>AC, all we can show is
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