Question #199448

A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves

the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher.

What is the magnitude of the impulse delivered to the baseball?

7.00 Ns


1
Expert's answer
2021-05-27T09:59:08-0400

Since the resultant momentum is at 90° relative to the initial, the change in momentum is


Δp=(mv1)2+(mv2)2=7 Ns.\Delta p=\sqrt{(mv_1)^2+(mv_2)^2}=7\text{ Ns}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS