Answer to Question #199447 in Physics for Dan

Question

The ISS in the orbit 408 km away from the surface of the earth. Calculate the time taken to orbit the earth. 

Answer 1

$$T=2\pi\sqrt{\frac{R^3}{GM}}\\T=2\pi\sqrt{\frac{(408\cdot10^{3}+6371\cdot10^{3})^3}{(6.67\cdot10^{-11})(5.97\cdot10^{24})}}=5560\ s$$