Answer to Question #185601 in Physics for zaydie

Question #185601

Christine, with mass m rides on a Ferris wheel

as shown in the figure. Christine moves in a

vertical circle of radius 10.0m with constant

speed of 3.00 m/s. Determine the force exerted

by the seat on Christine at the bottom of the

ride. Express your answer in terms of weight of

Christine, mg


1
Expert's answer
2021-04-28T13:03:07-0400

The centripetal force is


Fc=mv2R.F_c=m\frac{v^2}{R}.

The weight is


Fg=mg.F_g=mg.

The normal force is


N=Fc+Fg= =m(g+v2R).N=F_c+F_g=\\\space\\ =m\bigg(g+\frac{v^2}{R}\bigg).

Expressed terms of weight of Christine, mg, it is


Nmg=[Nmg]=[1+v2gr]mg=1.09mg.N_{mg}=\bigg[\frac{N}{mg}\bigg]=\bigg[1+\frac{v^2}{gr}\bigg]mg=1.09mg.



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