Question

An inclined plane is 3.5 m long and rises o.95 meters. The weight of the object on the inclined plane is 9.6 N. Find a) angle of the inclined plane ? , b) What is the normal force ? , and c) The force to move the object.

Answer 1

a) The angle of the inclined plane is

$$\theta=\arcsin\frac{0.95}{3.5}=15.7º.$$

b) The normal force is

$$N=W\cos\theta=9.6\cos15.7º=9.24\text{ N}.$$

c) The force to move the object

To move the object up the incline at constant velocity, the following force is required:

$$F=W\sin\theta=9.6\sin15.7º=2.60\text{ N}.$$