Question

A 45 kg table is sliding on the floor. If 25 kg force is required to start it in motion and 34 kg force to main Its motion, Find : a) coefficient of static friction and b) coefficient of static friction

Answer 1

The force of static friction is greater than the force of kinetic friction. Most likely, there's a mistake in the condition: 34 kg force is required to start its motion and 25 kg force to maintain Its motion. So, find:

a) the coefficient of static friction:

$$\mu_s=34/45=0.76.$$

b) coefficient of kinetic friction:

$$\mu_k=\frac{25}{45}=0.56.$$