A jet lands on an aircraft carrier at 63 m/s.
a) What is its acceleration (assumed constant) if it stops in 2.0 s due to an
arresting cable that snags the airplane and brings it to a stop?
b) If the plane touches down at position xo=0m, what is the final position of
the plane?
(a)
"v=v_0-at\\to a=v_0\/t=63\/2=31.5\\ (m\/s^2)" . Answer
(b)
"x=v_0^2\/(2a)=63^2\/(2\\cdot31.5)=63\\ (m)" . Answer
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