Question

 Solve the problems and show the complete solution.

1. An electron is moving at 30∘ to a magnetic field of strength B = 0.5x10-4 T at a speed of v = 1000m/s. What is the magnitude of the Lorentz force acting upon it? F = q v B sin θ

Answer 1

$$F = q v B \sin θ\\F = (1.6\cdot10^{-19})(1000)(0.5\cdot10^{-4}) \sin{30}\\=4\cdot10^{-21}\ N$$