Answer to Question #176536 in Physics for Chimka

Question

A car gravelling initially at 16m/s begins to accelerate at 4m/s . find the speed and distance covered at 3 minute

Answer 1

The speed covered after 3 minutes (180 s) of acceleration at 4 m/s² from 16 m/s:

$v=v_0+at=16+4·180=736\text{ m/s}.$

The distance covered during the three minutes:

$d=v_0t+\frac{at^2}{2}=67680\text{ m}.$

However, it is unclear whether we need to find the distance the car traveled during the third minute or during the three minutes. If during the third minute: find the distance covered during 2 minutes of such acceleration:

$d_2=v_0t_2+\frac{at_2^2}{2}=30720\text{ m}.$

The distance covered during the third minute:

$d_3=d-d_2=36960\text{ m}.$