Answer to Question #173365 in Physics for Richard

Question

A box weighing 225 N accelerates along a flat surface under the action of a force of intensity 14.6 N at an angle of 19 °. Determine the horizontal component of the box acceleration. When calculating, ignore any friction effects between the box and the surface of the substrate.

Answer 1

Let's first calculate the mass of the box:

$$m=\dfrac{W}{g}=\dfrac{225\ N}{9.8\ \dfrac{m}{s^2}}=22.96\ kg.$$

Then, let's find the horizontal component of the force acting on the box:

$$F_h=Fcos\theta=14.6\ N\cdot cos19^{\circ}=13.8\ N.$$

Finally, we can find the horizontal component of the box acceleration:

$$a_h=\dfrac{F_h}{m}=\dfrac{13.8\ N}{22.96\ kg}=0.6\ \dfrac{m}{s^2}.$$