Question #173364

The body was released to fall freely from a height of 100 m above the Earth's surface. Determine its speed just before hitting the ground. When considering this problem ignore air resistance.


1
Expert's answer
2021-03-21T11:24:05-0400
PE=KE,PE=KE,mgh=12mv2,mgh=\dfrac{1}{2}mv^2,v=2gh=29.8 ms2100 m=44.27 ms.v=\sqrt{2gh}=\sqrt{2\cdot9.8\ \dfrac{m}{s^2}\cdot100\ m}=44.27\ \dfrac{m}{s}.

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