Answer to Question #172063 in Physics for Ashley

Question

A particle has a charge of q = +5.1 μC and is located at the origin. As the drawing shows, an electric field of E_x = +214 N/C exists along the +x axis. A magnetic field also exists, and its x and y components are B_x = +1.2 T and B_y = +1.5 T. Calculate the force (magnitude and direction) exerted on the particle by each of the three fields when it is (a) stationary, (b) moving along the +x axis at a speed of 345 m/s, and (c) moving along the +z axis at a speed of 345 m/s.

Answer 1

a)

$$F_{Bx}=F_{By}=0\ N\\F_E=(5.1\cdot10^{-6})(214)=1.09\cdot10^{-3}\ N$$

Direction: along the + x axis

b)

$$F_E=(5.1\cdot10^{-6})(214)=1.09\cdot10^{-3}\ N$$

Direction: along the + x axis

$$F_{Bx}=0$$ $$F_{By}=(5.1\cdot10^{-6})(1.5)(345)=2.64\cdot10^{-3}\ N$$

Direction: along the + z axis

c)

$$F_E=(5.1\cdot10^{-6})(214)=1.09\cdot10^{-3}\ N$$

Direction: along the + x axis

$$F_{By}=(5.1\cdot10^{-6})(1.5)(345)=2.64\cdot10^{-3}\ N$$

Direction: along the - x axis

$$F_{Bx}=(5.1\cdot10^{-6})(1.2)(345)=2.11\cdot10^{-3}\ N$$

Direction: along the + y axis