Question #171958

A bullet is fired perpendicular upwards into the air and leaves the barrel at 200m/s. answer the following questions:

1.How long would it take before bullet has an upward velocity at 80 m/s?
2.How long would it take before the bullet reaches its maximum height?
3.What will the velocity of the bullet be after 15 s?
Chat started

Expert's answer

1)

v=v0+gt,v=v_0+gt,t=80 ms200 ms9.8 ms2=12.24 s.t=\dfrac{80\ \dfrac{m}{s}-200\ \dfrac{m}{s}}{-9.8\ \dfrac{m}{s^2}}=12.24\ s.

2)

0=v0+gt,0=v_0+gt,t=v0g=200 ms9.8 ms2=20.41 s.t=\dfrac{-v_0}{g}=\dfrac{-200\ \dfrac{m}{s}}{-9.8\ \dfrac{m}{s^2}}=20.41\ s.

3)

v(t=15 s)=200 ms+(9.8 ms2)15 s=53 ms.v(t=15\ s)=200\ \dfrac{m}{s}+(-9.8\ \dfrac{m}{s^2})\cdot15\ s=53\ \dfrac{m}{s}.
LATEST TUTORIALS
APPROVED BY CLIENTS