Question #171709

A rifle bullet with mass 8.00 g strikes and embeds itself in a block with mass 0.992 kg that rests on a frictionless, horizontal surface and is attached to a coil spring (as shown below). The impact compresses the spring 15.0 cm. Calibration of the spring shows that a force of 0.750 N is required to compress the spring 0.250 cm.


a) Find the magnitude of the block’s velocity just after impact.

b) What was the initial speed of the bullet?



1
Expert's answer
2021-03-16T11:36:41-0400

a)


k=0.75(100)0.25=300Nmk=\frac{0.75(100)}{0.25}=300\frac{N}{m}

0.5(m+M)v2=0.5kx2(0.008+0.992)v2=(300)(0.15)2v=2.60ms0.5(m+M)v^2=0.5kx^2\\(0.008+0.992)v^2=(300)(0.15)^2\\v=2.60\frac{m}{s}

b)


(m+M)v=mu(0.008+0.992)2.6=0.008uu=325ms(m+M)v=mu\\(0.008+0.992)2.6=0.008u\\u=325\frac{m}{s}


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