Question

The modulus of rigidity and Poisson’s ratio of the material of a wire are 2.87 × 1010 N/m2, and 0.379 respectively. Estimate the Young’s modulus of the material of the wire. 

Answer 1

The relation between the modulus of rigidity $G$, Poisson’s ratio $\nu$, and the Young’s modulus $E$ is the following:

$$E = 2G(1+\nu)$$

Substituting the numbers, obtain:

$$E = 2\cdot 2.87\times 10^{10}\cdot (1 + 0.379) \approx 7.92\times 10^{10}\dfrac{N}{m^2}$$

Answer. $7.92\times 10^{10}\dfrac{N}{m^2}$.