(a) Let's first find the total distance traveled:
dtot=d1+d2+d3,dtot=v1t1+v2t2+v3t3,dtot=25 hkm⋅(4 min⋅60 min1 h)+50 hkm⋅(8 min⋅60 min1 h)+20 hkm⋅(2 min⋅60 min1 h)=9 km.
(b) We can find the average speed for the complete trip as follows:
vavg=ttotdtot,vavg=4 min⋅60 min1 h+8 min⋅60 min1 h+2 min⋅60 min1 h9 km,vavg=38.57 hkm⋅1 km1000 m⋅3600 s1 h=10.71 sm.
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