Answer to Question #168610 in Physics for zena

Question #168610

The maximum kinetic energy of the photoelectrons is 1.44 x 10-18J. What is the stopping potential?

Expert's answer

We can find the stopping potential as follows:

K_{max}=qV_0,

V_0=\dfrac{K_{max}}{q}=\dfrac{1.44\cdot10^{-18}\ J}{1.6\cdot10^{-19}\ C}=9\ V.

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