Answer to Question #168610 in Physics for zena

Question

The maximum kinetic energy of the photoelectrons is 1.44 x 10-18J. What is the stopping potential?

Answer 1

We can find the stopping potential as follows:

$$K_{max}=qV_0,$$ $$V_0=\dfrac{K_{max}}{q}=\dfrac{1.44\cdot10^{-18}\ J}{1.6\cdot10^{-19}\ C}=9\ V.$$