Question

The forces F1 = 150N and F2 = 50N with opposite direction are shown and the distance between their lines of action is l = 120cm. Determine the value of the resulting force, the direction and position for its point of application.

Answer 1

The value of the resulting force:

$$R=F_1-F_2=100\text{ N}.$$

The direction and position for the point of application of this force is in the direction of the 150N-force.