Question

9. Using a wrench we fix a nut with diameter d = 2.5 cm. In this case, the torque F = 40 N. is applied on the key handle. Calculate the force exerted by the key on the perimeter of the nut, when it is known that the key handle is 25 cm long.

Answer 1

$$F'd=Fl\\(2.5)F'=(25)(40)\\F'=400\ N$$