Question

If a boy tosses a ball straight up with an initial velocity of 13m/s what .how long does the ball take at it's highest

Answer 1

The velocity of the ball before it reaches the highest point is given as follows:

$$v = v_0 -gt$$

where $v_0 = 13m/s$ is the initial speed, $g = 9.81m/s^2$ is the gravitational acceleration, and $t$ is the time. At the highest point $v = 0$. Thus, the moment of time is:

$$0 = v_0 - gt_h\\ t_h = \dfrac{v_0}{g}\\ t_h = \dfrac{13}{9.81}\approx 1.33s\\$$

Answer. 1.33s