Answer to Question #160322 in Physics for Kimora Stowe

Question

A 2 8x10 kg jet plane is ready for takeoff. The jet's engines supply a constant thrust of 6.35x10'N How much runway will it need to reach a minimum takeoff speed of 285km/hr? What is the normal force acting on the jet?

Answer 1

$285(km/h)=79.2(m/s)$

$m=2.8\cdot10^5(kg)$

$F=6.35\cdot 10^6(N)$

$a=F/m=6.35\cdot10^6/(2.8\cdot10^5)=22.7(m/s^2)$

$s=\frac{79.2^2}{2\cdot22.7}=138.1(m)$ . Answer

$N=mg=2.8\cdot10^5\cdot 9.8=2.744\cdot 10^6\ (N)$ . Answer