Answer to Question #160292 in Physics for Nana

Question #160292

The vertical and horizontal components of the initial velocity of a projectile are 36m/s and 64m/s find the initial velocity

Expert's answer

"v_x=\\sqrt{v_h^2+v_v^2}=\\sqrt{(36\\ \\dfrac{m}{s})^2+(64\\ \\dfrac{m}{s})^2}=73.43\\ \\dfrac{m}{s}."

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