Question #159654

Given the wave equation y(x,t) =2.0 Sin (3.0x-4.0t + π/2)m, where x is in meter and t is in second. Find the:

a) amplitude

b)Frequency

c) wavelength

d)speed

e) initial height at x=1.0m


1
Expert's answer
2021-01-31T03:40:04-0500

The general equation of wave is:


y(x,t)=Asin(kxωt+φ0)y(x,t) = A\sin(kx-\omega t + \varphi_0)

where k=2πλk = \dfrac{2\pi}{\lambda} is the wave number (λ\lambda is the wavelength), ω=2πf\omega = 2\pi f is the angular frequency (ff is the frequency), AA is the amlitude, and φ0\varphi_0 is the initial phase.

Comparing the general equation with the given one, find:


A=2mA = 2mω=4rad/sf=42π0.64Hz\omega = 4rad/s \Rightarrow f =\dfrac{4}{2\pi} \approx 0.64Hzk=3m1λ=2π32.09mk = 3m^{-1}\Rightarrow\lambda = \dfrac{2\pi}{3} \approx 2.09m

Speed of the wave is given as:


v=fλ=0.642.06m/s1.33m/sv = f\lambda = 0.64\cdot 2.06m/s \approx 1.33m/s


Substituting x=1mx = 1m, t=0t = 0, find:


y(1,0)=2sin(3140+π/2)0.16my(1,0) = 2\sin(3\cdot 1 - 4\cdot0 + \pi/2) \approx 0.16m

Answer. a) 2m, b) 0.64Hz, c) 2.09m, d) 1.33 m/s, e) 0.16m


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