a) F=∣q∣vBsinα=1.6⋅10−19⋅8⋅106⋅0.025⋅sin60°=2.77⋅10−14 (T)
a=F/m=2.77⋅10−14/9.1⋅10−31=3⋅1016 (m/s2)
b) qvBsin60°=m(v⋅sin60)2/r and T=2πr/(v⋅sin60°)→ T=qB2πm=
=1.6⋅10−19⋅0.0252⋅3.14⋅9.1⋅10−31=1.43⋅10−9 (s)
r=qBvm⋅sin60°=1.6⋅10−19⋅0.0258⋅106⋅9.1⋅10−31⋅sin60°=0.0016 (m)
h=v⋅cos60°⋅T=8⋅106⋅cos60°⋅1.43⋅10−9=0.00572 (m)
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