Question #158040

The Riccati equation is a nonlinear differential equation that is of considerable importance in particle dynamics. By use of a change of the dependent variable y = -[1/P(x)]dz/dx, show that the Riccati differential equation becomes the one below on the ending point. Notice that the resulting transformation is a second-order linear differential equation.


Starting point:

(dy/dx) =P(x) y^2 +Q(x) y +R(x)


Ending point:

(d^2z/dx^2)-(Q+(1/p)(dp/dx) ) dz/dx +PRz=0


1
Expert's answer
2021-01-25T13:56:48-0500
y2=1P2(dzdx)2dydx=1Pd2zdx2+1P2dzdxdPdxy^2=\frac{1}{P^2}\left(\frac{dz}{dx}\right)^2\\\frac{dy}{dx}=-\frac{1}{P}\frac{d^2z}{dx^2}+\frac{1}{P^2}\frac{dz}{dx}\frac{dP}{dx}

1Pd2zdx2+1P2dzdxdPdx=1P(dzdx)2Q1Pdzdx+R-\frac{1}{P}\frac{d^2z}{dx^2}+\frac{1}{P^2}\frac{dz}{dx}\frac{dP}{dx}=\frac{1}{P}\left(\frac{dz}{dx}\right)^2-Q\frac{1}{P}\frac{dz}{dx}+R

d2zdx21PdzdxdPdx+(dzdx)2Qdzdx+RP=0\frac{d^2z}{dx^2}-\frac{1}{P}\frac{dz}{dx}\frac{dP}{dx}+\left(\frac{dz}{dx}\right)^2-Q\frac{dz}{dx}+RP=0


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