Question #157893

You’re involved in the design of a mission carrying humans to the surface of the 

planet Mars, which has a radius 3.37x106m and a mass of 6.42x1023 kg. The 

earth weight of the Mar’s lander is 39,200 N. Calculate its weight and the 

acceleration due to Mar’s gravity at 6.0 x 106 m above the surface of Mars.


1
Expert's answer
2021-01-23T19:34:58-0500
gM=GMM(RM+h)2,g_M=\dfrac{GM_M}{(R_{M}+h)^2},gM=6.71011 Nm2kg26.421023 kg(3.37106 m+6106 m)2=0.49 ms2.g_M=\dfrac{6.7\cdot10^{-11}\ \dfrac{Nm^2}{kg^2}\cdot 6.42\cdot10^{23}\ kg}{(3.37\cdot10^6\ m+6\cdot10^6\ m)^2}=0.49\ \dfrac{m}{s^2}.

The mass of the Mar’s lander:


m=Wg=39200 N9.8 ms2=4000 kg.m=\dfrac{W}{g}=\dfrac{39200\ N}{9.8\ \dfrac{m}{s^2}}=4000\ kg.

The weight of the Mar’s lander at a height h=6106 mh=6\cdot10^6\ m above the surface of Mars will be:


W=mgM=4000 kg0.49 ms2=1960 N.W=mg_M=4000\ kg\cdot0.49\ \dfrac{m}{s^2}= 1960\ N.

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