Question

Calculate the period of simple pendulum in the following lengths.

a) 3.0 m

b) 6.0

c) 9.0

d) 12.0

Answer 1

a)

$$T=2\pi\sqrt{\dfrac{L}{g}}=2\pi\sqrt{\dfrac{3.0\ m}{9.8\ \dfrac{m}{s^2}}}=3.47\ s.$$

b)

$$T=2\pi\sqrt{\dfrac{6.0\ m}{9.8\ \dfrac{m}{s^2}}}=4.92\ s.$$

c)

$$T=2\pi\sqrt{\dfrac{9.0\ m}{9.8\ \dfrac{m}{s^2}}}=6.02\ s.$$

d)

$$T=2\pi\sqrt{\dfrac{12.0\ m}{9.8\ \dfrac{m}{s^2}}}=6.95\ s.$$