Question

A ball rolls off a 1.10-meter high table with an initial horizontal velocity of 3.3 m/s. Determine the time required for the ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location

Answer 1

We can find the time required for the ball to fall to the ground from the equation of motion of the ball in vertical direction:

$$y=\dfrac{1}{2}gt^2,$$ $$t=\sqrt{\dfrac{2y}{g}},$$ $$t=\sqrt{\dfrac{2\cdot 1.10\ m}{9.8\ \dfrac{m}{s^2}}}=0.47\ s.$$

We can find the horizontal distance between the table's edge and the ball's landing location from the equation of motion of the ball in horizontal direction:

$$x=v_0t=3.3\ \dfrac{m}{s}\cdot 0.47\ s=1.55\ m.$$

Answer:

$t=0.47\ s.$

$x=1.55\ m.$